Change in volume when 10 ml of phosphine is decomposed :
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7
hey here is your answer ______________________________
The Equation for the decomposition is..
4PH3 = P4 + 6H2
( Elemental Phosphorus exists as tetraatomic molecules)
-->> When the temperature and pressure remain the same..
4ml of PH3 will give 6ml of H2
( On applying Gay-Lussac's lew)
Hence ,
10 ml of PH3 will yield (10/4)×6ml of H2
10 ml of PH3 will yield 15ml of H2
then ...
Increase in volume = 15-10=5ml
(The volume of solid Phosphorus is negligible)
there is a 50% Increase in volume..
I am not sure but I hope it will help you for getting answer
The Equation for the decomposition is..
4PH3 = P4 + 6H2
( Elemental Phosphorus exists as tetraatomic molecules)
-->> When the temperature and pressure remain the same..
4ml of PH3 will give 6ml of H2
( On applying Gay-Lussac's lew)
Hence ,
10 ml of PH3 will yield (10/4)×6ml of H2
10 ml of PH3 will yield 15ml of H2
then ...
Increase in volume = 15-10=5ml
(The volume of solid Phosphorus is negligible)
there is a 50% Increase in volume..
I am not sure but I hope it will help you for getting answer
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Deepsbhargav:
sorry
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2
I thought this will be the answer .
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