Question

change in volume when 100 ml PH3 decomposed to solid p &H2gas.

Answer 1

Hey Mate,

Here Is Your Answer

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The equation for the decomposition is:

4PH3 (g) = P4 (s)+ 6H2 (g) (Elemental phosphorus exists as tetraatomic molecules).

When the temperature and pressure remain the same, 4 ml of PH3 will give 6 ml of H2. (On applying Gay-Lussac's law ).

Hence, 100 ml of PH3 will yield 150 ml of H2.

Increase in volume = (150-100) ml = 50 ml. (The volume of solid phosphorus is negligible).

There is a 50% increase in volume.

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Hope,It Will Help You.

Answer 2

Hey dear,

● Answer -
∆V = +50 ml

● Explanation -
Decomposition of phosphine on heating gives solid phosphorus and hydrogen gas.
Reaction is expressed as -
2PH3(g) ---> 2P(s) + 3H2(g)

Here, 2 L of PH3 gas => 3 L of H2 gas
Thus, 100 ml of PH2 => 100×3/2=150 ml of H2.

Change in volume is -
∆V = 150 - 100
∆V = 50 ml

Therefore, change in volume is +50 ml.

Hope this helps you...