the sum of a 2 digit no. and no. obtained by reversing the order of digits is 99. if the digits of number differ by 3. Find the number
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10x(x+3) is the equyion of this equation
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let the digit at tens place be x
then the digit at ones place will be x+3
so the no. can be written as 10x + (x+3) in extended form
on reverseing the number we get
10(x+3) +x
now adding the two numbers will give 99 according to question.
so,
10x + (x+3) + 10(x+3) + x = 99
10x + x + 3 + 10x + 30 + x = 99
22x = 66
x=3
so the number is 36 and 63
hope it helps.
then the digit at ones place will be x+3
so the no. can be written as 10x + (x+3) in extended form
on reverseing the number we get
10(x+3) +x
now adding the two numbers will give 99 according to question.
so,
10x + (x+3) + 10(x+3) + x = 99
10x + x + 3 + 10x + 30 + x = 99
22x = 66
x=3
so the number is 36 and 63
hope it helps.
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