Math, asked by lakrasisir2021, 1 day ago

Chapter=11 PERIMETER AND AREA
E. Solve:
2. A swimming pool is 12.5m long and 11m breadth. Find its area.​

Answers

Answered by Anonymous
29

Given :

  • Length = 12.5 m
  • Breadth = 11 m

 \\ \\

To Find :

  • Find the Area

 \\ \qquad{\rule{200pt}{2pt}}

SolutioN :

 \dag Formula Used :

  •  {\underline{\boxed{\pmb{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}}

 \\ \\

 \dag Calculating the Area :

 {\longmapsto{\qquad{\sf{ Area = Length \times Breadth }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Area = 12.5 \times 11 }}}} \\ \\ \\ \ {\longmapsto \; {\pmb{\underline{\boxed{\purple{\frak{ Area = 137.5 \; {m}^{2} }}}}}}}

 \\ \\

 \therefore \; Area of the Swimming pool is 137.5 .

 \\ \qquad{\rule{200pt}{2pt}}

Answered by Rina86169
4

Step-by-step explanation:

Given :

Length = 12.5 m

Breadth = 11 m

 \\ \\

To Find :

Find the Area

 \\ \qquad{\rule{200pt}{2pt}}

SolutioN :

 \dag Formula Used :

 {\underline{\boxed{\pmb{\sf{ Area{\small_{(Rectangle)}} = Length \times Breadth }}}}}

 \\ \\

 \dag Calculating the Area :

 {\longmapsto{\qquad{\sf{ Area = Length \times Breadth }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ Area = 12.5 \times 11 }}}} \\ \\ \\ \ {\longmapsto \; {\pmb{\underline{\boxed{\purple{\frak{ Area = 137.5 \; {m}^{2} }}}}}}}

 \\ \\

 \therefore \; Area of the Swimming pool is 137.5 m² .

 \\ \qquad{\rule{200pt}{2pt}}

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