Question

chapter : Area of plane figures.

Detailed answer needed.

Spam = 10 answers report.

Paper answer requested.​

Answer 1

Answer:

the above is your answer

hope it helps

don't mind my writting

Answer 2

Answer:

$\bf \huge \underline{Solution}$

$\bf \underline{GIVEN:}$

OA = OB = OC = OD = 14CM

there are 2 semicircles and 2 quadrant

radius of quadrant = 14cm

radius of semicircle = 14÷2= 7cm

Area of quadrant AOC

= $\frac{1}{4}$ × π × r²

= $\frac{1}{4}$ × $\frac{22}{7}$ × 14²

= 154 cm ²

Area of non shaded part of quadrant [ basically a semicircle ]

= $\frac{1}{2}$ × π × r²

[ given : radius = 7cm ]

= $\frac{1}{2}$ × $\frac{22}{7}$ × 7²

= 77cm²

Area shaded part of AOC

= total area of AOC - un shaded part of AOC

= 154cm² - 77cm²

= 77cm²

AREA OF SEMICIRCLE AOD

= $\frac{1}{2}$ × π × r²

= $\frac{1}{2}$ × $\frac{22}{7}$ × 7²

= 77cm²

➥TOTAL AREA OF THE FIGURE =

= 2 [ Area of AOC + Area of AOC ]

= 2 [ 77cm² + 77cm² ]

= 2 [ 154cm² ]

= 308 cm²

∴ the total surface area is = 308cm²

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