Question

Chapter : Electricity

Solve with a Proper Explanation :)

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Answer 1

Answer :

First of all, See the attachment for better understanding about circuit$.$

◈ It's clear from the circuit that, all four resistors are in series.

Equivalent resistance :-

➝ Req = R + R + R + R

➝ Req = 4R

➝ Req = 40Ω

◈ Potential difference across AB is 10V.

As per ohm's law,

➝ V(AB) = I×Req

➝ 10 = I×40

➝ I = 10/40

➝ I = 0.25A

◈ We know that, same current flow through each resistor in series connection.

Hence, current flow through all four resistor will be 0.25A.

◈ Potential drop across each resistor :

➝ V = IR

➝ V = 0.25 × 10

➝ V = 2.5 volt

Now come to the question! :D

✻ Reading of V(2) :

➠ Reading of V(2) = 0 volt

[because there is no resistor present between terminals of second voltmeter.]

✻ Relation b/w reading of V(1) and V(3) :

There are two resistors present between terminals of both voltmeters. Hence, both voltmeter will show same reading.

➠ Reading = 2 × 2.5 = 5 volt

Therefore, V(1) = V(3)

✻ Relation b/w reading of V(1) and V(4) :

There are two resistors present between terminals of first voltmeter whereas one resistor present between terminals of fourth resistor.

➠ Reading of V(1) = 2 × 2.5 = 5V

➠ Reading of V(4) = 1 × 2.5 = 2.5V

Therefore, V(1) = 2V(4)

Answer 2

Answer :

First of all, See the attachment for better understanding about circuit..

◈ It's clear from the circuit that, all four resistors are in series.

Equivalent resistance :-

➝ Req = R + R + R + R

➝ Req = 4R

➝ Req = 40Ω

◈ Potential difference across AB is 10V.

As per ohm's law,

➝ V(AB) = I×Req

➝ 10 = I×40

➝ I = 10/40

➝ I = 0.25A

◈ We know that, same current flow through each resistor in series connection.

Hence, current flow through all four resistor will be 0.25A.

◈ Potential drop across each resistor :

➝ V = IR

➝ V = 0.25 × 10

➝ V = 2.5 volt

Now come to the question! :D

✻ Reading of V(2) :

➠ Reading of V(2) = 0 volt

[because there is no resistor present between terminals of second voltmeter.]

✻ Relation b/w reading of V(1) and V(3) :

There are two resistors present between terminals of both voltmeters. Hence, both voltmeter will show same reading.

➠ Reading = 2 × 2.5 = 5 volt

Therefore, V(1) = V(3)

✻ Relation b/w reading of V(1) and V(4) :

There are two resistors present between terminals of first voltmeter whereas one resistor present between terminals of fourth resistor.

➠ Reading of V(1) = 2 × 2.5 = 5V

➠ Reading of V(4) = 1 × 2.5 = 2.5V

Therefore, V(1) = 2V(4)