Question

protractor.
11. The perimeter of a rhombus is equal to the circumference of a circle. If each side of the
rhombus measures 11 cm, then find the radius of the circle.
2. A piece of thin wire in the form of an equilateral triangle of side 88 dm in hont int​

Answer 1

Step-by-step explanation:

11.) perimeter of a rhombus = 4×side

here, side is given 11cm

then, 4×11=44cm

circumference of a circle = 2×22/7×r

2×22/7×r= 44cm

r= 44×7/2×22= 7cm

radius = 7cm

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Answer 2

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• Measure of each Side of rhombus is, a = 11cm

• Perimeter of rhombus is equal to the circumference of Circle.

${ \huge{ \underline{ \underline{ \sf{ \green{To \: find :}}}}}}$

• What's the radius of circle?

Formula to be used :-

• Perimeter of a rhombs = 4a

Where, a = side

• Circumference of circle = 2πr

${ \huge{ \underline{ \underline{ \sf{ \green{SoluTion : }}}}}}$

Given that,

Perimeter of rhombus is equal to the circumference of Circle.

Therefore, we need to find the value of perimeter of the given rhombs.

Here,

Perimeter of rhombs

= 4a

= 4 × 11 cm

= 44 cm

According to the question :-

Circumference of circle = Perimeter of rhombus.

⟶ 2πr = 44

⟶ πr = 44/2

⟶ πr = 22

⟶ 22/7 × r = 22

⟶ r = 7cm

Hence, radius of circle is = 7cm.