Math, asked by shawramkumar83, 3 months ago

Chapter - Linnear simulation equation
Please help
whose any answer is correct i give it brainlieast answer​

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Answers

Answered by karmaan958
1

Step-by-step explanation:

1.) 3x + 4y = 17 (eqn. no. 1)

4x - 3y = 6 (eqn. no. 2)

(equal the value of x or y in both the eqn.)

[multiplying eqn no. 1 by 4 and eqn no. 2 by 3]

4(3x + 4y = 17)

12x + 16y = 68

12x + 16y - 68 = 0 (eqn. no. 3)

3(4x - 3y = 6)

12x - 9y = 18

12x - 9y - 18 = 0 (eqn. no. 4)

[eliminating x by subtracting eqn no. 3 by eqn. no. 4]

12x + 16y - 68 - (12x - 9y - 18) = 0

= 12x + 16y - 68 - 12x + 9y + 18 = 0

= 25y - 50 = 0

= 25y = 50

y = 50/25

y = 2

[ putting the value of y in eqn. no. 1]

3x + 4y = 17

3x + 4(2) = 17

3x + 8 = 17

3x = 17 - 8

3x = 9

x = 9/3

x = 3

2.) 2x + 3y - 5 = 0 (eqn. no. 1)

3x + 2y - 5 = 0 (eqn. no. 2)

(equal the value of x or y in both the eqn.)

[multiplying eqn no. 1 by 3 and eqn no. 2 by 2]

3(2x + 3y - 5 = 0)

6x + 9y - 15 = 0 (eqn. no. 3)

2( 3x + 2y - 5 = 0)

6x + 4y - 10 = 0 (eqn. no. 4)

[eliminating x by subtracting eqn no. 3 by eqn. no. 4]

6x + 9y - 15 - (6x + 4y - 10) = 0

6x + 9y - 15 - 6x - 4y + 10 = 0

5y - 5 = 0

5y = 5

y = 5/5

y = 1

[ putting the value of y in eqn. no. 1]

2x + 3y - 5 = 0

2x + 3(1) - 5 = 0

2x + 3 - 5 = 0

2x - 2 = 0

2x = 2

x = 2/2

x = 1

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