Question

CHAPTER-PLAYING WITH NUMBER
the sum of the digits of a 2 digit number is 7. if the digits are reversed the new number increased by 3 less than 4 times the original number find the original number


PLS HELP ME WITH THIS QUESTION​

Answer 1

Answer:

Step-by-step explanation:

Let the ones's digit =x.

So, sum of the digits =7

Tens's digit =7−x

Original no. =10(7−x)+x=70−10x+x=70−9x

Reversed no. =10x+7−x=9x+7

2(orig no) = reversed no. −2

2(70−9x)=9x+7−2

140−18x=9x+5

27x=135

x=5

Ten's digit =7−5=2

No. =25

Hope it is helpful!!