Question

chapter probability class 10 try to answer correctly

Answer 1

1.Since one card is drawn at random, Hence total number of possible outcomes =122
If E is event"a square number"
Then E=(16,25,36,.......,121)
Therefore n(E) =7
Hence, P(E) =1/122*7=0.075
2.(a multiple of seven) =P(14,21,......119)=15/122=0.22

Answer 2

Total number of possible outcomes =112

If E is event"a square number"

Then E=(16,25,36,.......,121)

Therefore n(E) =7

Hence, P(E) =$\frac{7}{112}$=$\frac{1}{16}$

P(a multiple of seven) = (14,21,......119) = $\frac{16}{112} = \frac{1}{7}$

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