Question

Chapter Test
10000 was lent for one year at 10% per annum. By how much more will the interest
be, if the sum was lent at 10% per annum, interest being compounded half-yearly?​

Answer 1

Here P = 10,000

R = 10%

T = 1 year

A = p ( 1 + r/100) ki power n

A = 10000 ( 1 + 5 / 100 )ki power 2

by solving we get

A = 11025

C.I = A - P

= 11025 - 10000

= 1025

now S.I = p × r × t/100

S.I = 10000 × 10 × 1/100

S.I = 1000

Difference in interest = 1025 - 1000 = 25