chapter understanding quadrilateral
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Given, one angle of ||gm is 50° = A
angle A = angle C (opp angles of ||gm are equal)
Therefore, angle C = 50°
Angle B + angle C = 180° (angles on the same side of transversal)
B + 50 = 180
Angle B = 130°
Angle B = Angle D(opp Angles of ||gm)
Angle D= 130°
Angle A= 50°
Angle B= 130°
Angle C= 50°
Angle D= 130°
Hence, proved
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