Question

charge of an iron particle of mass 224 mg, if 0.01% of
the electrons are removed from it.
​

Answer 1

Answer:

mass number of Fe = 56 g

mass number of Fe = 56 gmoles of Fe = 22.4/56 =0.4

mass number of Fe = 56 gmoles of Fe = 22.4/56 =0.4no of electrons in 0.4 moles= 0.4*6.023*10 to power 23 =2.4092*10 to power 23

mass number of Fe = 56 gmoles of Fe = 22.4/56 =0.4no of electrons in 0.4 moles= 0.4*6.023*10 to power 23 =2.4092*10 to power 23when .01% electrons are removed then left no of electrons =2.4089*10^23

mass number of Fe = 56 gmoles of Fe = 22.4/56 =0.4no of electrons in 0.4 moles= 0.4*6.023*10 to power 23 =2.4092*10 to power 23when .01% electrons are removed then left no of electrons =2.4089*10^23charge on iron 2.4089*10^23*1.6*10^-19= 38543.34 C

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