Question

Charge passing through the cross section of a conductor is given by
Q=B+A't.
What will be the
current at time t = 10 see?
(a) 5A
(b) 10A
(c) 20A
(d) 40 A
​

Answer 1

Answer:

Charge Q=5t

2

−2t

At t=2s,Q(2)=5×4−2×2=16C

At t=4s,Q(4)=5×16−2×4=72C

Current is given by: I=

Δt

ΔQ

2

72−16

=

2

56

=28A

Explanation:

(b) 10A

Answer 2

Concept Introduction:-

A conductor is the object that permits electricity to flow through it in the physics as well as electrical engineering charge to flow either in a single direction or numerous ones.

Given Information:-

We have been given that charge passing through the cross section of a conductor is given by $Q=B+A't$.

To Find:-

We have to find that the current at time $t = 10$ see.

Solution:-

According to the problem

$Q=B^{\prime}+A^{\prime} t^{2}$

$I=\frac{d Q}{d t}=0+2 A^{\prime} t$

$I=2 A^{\prime} t\\t=10 \mathrm{sec}\\I=2 A^{\prime}(10)=20 A^{\prime} ampere$

Final Answer:-

The current time is $20A'$.

#SPJ2