Question

Charge q is uniformly distributed over a thin half ring of radius r

Answer 1

Answer:

Explanation:

As we learned

 

Charged Circular ring -

A charged circular ring of radius R and charge Q.

- wherein

 

From figure dl  = R d\theta ,

Charge on dl  = \lambda Rd\theta \left \{ \lambda \frac{q}{\pi R} \right \}

Electric field at centre due to dl is  dE=k\cdot \frac{\lambda Rd\theta }{R^{2}}\cdot

 

Option 1)

\frac{q}{2\pi ^{2}\varepsilon_{0}R^{2}}

Answer 2

Answer:

⚡answer in attachment ⚡