Question

charged oil drop of mass 2.5 x10-4gm is in space between two plates each of area 200 cm2 of a parallel plate capacitor. When the upper plate has a charge 5 x 10-7 C and the lower plate has an equal negative charge, the drop remains stationary. The charge of oil drop is​

Answer 1

Answer:

Mass =2.5×10

−7

kg

qE=mg

or, q×

Aϵ

0

Q

=mg

q=

Q

mgAϵ

0

=

5×C7×1

2.5×10

−2

×2×10

−2

×8.854×10

−12

×10