Charges 4Q, q and Q and placed along
x-axis at positions x=0, x=l/2 and x=l,
respectively. Find the value of q so that
force on charge Q is zero
Answers
Answered by
0
Answer:
The force exerted on the charge q,Q is given as follows.
F(q,Q)=k[
l
2
/4
]=
l
2
4kqQ
.
The force exerted on the charge q, 4q is given as follows.
F(q,4q)=k[
l
2
4q
2
]=
l
2
4kq
2
.
The net force = F(q,Q) + F(q,4q) = 0
l
2
4kqQ
+
l
2
4kq
2
=0
So, qQ+q
2
=0.
q[Q + q] =0
As, q cannot be = 0
Q + q =0
Therefore, Q = - q
Hence, Q should be -q in order to make the net force on q to be zero.
Similar questions