charges of +2 micro coulomb,+3micro coulomb and -8micro coulomb are placed at the vertices of an equilateral triangle of side 10 CM. calculate the magnitude of force acting on -8micro coulomb charge due to other two charges.
Answers
Answer:
Net electric field at A due to charges at B and C is
E
A
=2E
Ac
sin50
o
=2×9×10
9
×
(0.20)
2
3×10
−6
×
2
3
=
3
×6.75×10
5
AM=
(20)
2
−(10)
2
=
400−100
=10
3
cm
Let the charge at M be q. Charge q should be positive so that there can be repulsion between the charges at A and M.
E
AM
=9×10
9
×
(10
3
/100)
2
q
=3q×10
11
For A to be in equilibrium
E
A
=E
AM
⇒
3
×6.75×10
5
=3q×10
11
or q=
4
9
3
×10
−6
=
4
9
3
μC
Explanation:
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Explanation:
Particles of charge +65, +48, and −95 μC are placed in a line. The center one is L = 60cm from each of the others.Calculate the net force on the left charge due to the other two.
Physics
A point charge (m = 1.0 g) at the end of an insulating string of length L = 51 cm (Fig. 16-66) is observed to be in equilibrium in a uniform horizontal electric field of E = 9200 N/C, when the pendulum's position is as shown in Fig. 16-66, with the charge