Chemistry, asked by shashwatanand07, 6 months ago

Charles law can be represented as V(t) = a + bt
Where t is temperature in Celsius scale and a and b are constants.
Which of the following statements are correct?
(A) a is volume of the gas at 0 C, ie, V(0)
(B) b = V(0)/273 ( V(0) = volume of the gas at 0 C)
(C) Volume of a gas theoretically zero at 0 C
(D) V(t) < V(0)

Answers

Answered by ankanbanerjee2005
0

Answer:

SEE YA MATE

..The volume of a fixed mass of a gas decreases on cooling it and increases by increasing the temperature. For one degree rise in temperature, the volume of the gas increases by 1273 of its original volume at 0˚C. Let volume of the gas at 0˚C and t˚C be Vo and Vt respectively”.

The volume of a fixed mass of a gas decreases on cooling it and increases by increasing the temperature. For one degree rise in temperature, the volume of the gas increases by 1273 of its original volume at 0˚C. Let volume of the gas at 0˚C and t˚C be Vo and Vt respectively”.Then, Vt = Vo+t273.15Vo ……….. (i)

The volume of a fixed mass of a gas decreases on cooling it and increases by increasing the temperature. For one degree rise in temperature, the volume of the gas increases by 1273 of its original volume at 0˚C. Let volume of the gas at 0˚C and t˚C be Vo and Vt respectively”.Then, Vt = Vo+t273.15Vo ……….. (i)Vt = Vo(1+t273.15) ……….. (ii)

The volume of a fixed mass of a gas decreases on cooling it and increases by increasing the temperature. For one degree rise in temperature, the volume of the gas increases by 1273 of its original volume at 0˚C. Let volume of the gas at 0˚C and t˚C be Vo and Vt respectively”.Then, Vt = Vo+t273.15Vo ……….. (i)Vt = Vo(1+t273.15) ……….. (ii)Vt = Vo(273.15+t273.15) ………… (iii)

The volume of a fixed mass of a gas decreases on cooling it and increases by increasing the temperature. For one degree rise in temperature, the volume of the gas increases by 1273 of its original volume at 0˚C. Let volume of the gas at 0˚C and t˚C be Vo and Vt respectively”.Then, Vt = Vo+t273.15Vo ……….. (i)Vt = Vo(1+t273.15) ……….. (ii)Vt = Vo(273.15+t273.15) ………… (iii)We will now assign a new scale for temperature where the temperature in Celsius is given as t = T -273.15 and 0˚C can be given as To = 273.15. This new scale of temperature (T) is known as the Kelvin temperature scale or Absolute temperature scale. Degree sign is not written when a temperature is written in Kelvin scale. It is also known as the thermodynamic scale of temperature and it is commonly used in all scientific purposes. Thus, when we need to write temperature in Kelvin scale we add 273 to the temperature in Celsius.

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