Question

Charmi chowdary is observing an object from a building of height 6mts with 60° of anlge of depression,
then the horizontal distance between building and object is
[ 1
6
a) 6mts.
b) 613 mts
mts
d) none​

Answer 1

Answer:

cos 60° = base/hypotenuse

1/2=6/h

h×1=6×2

h=12 m

let horizontal distance between building and object be x

therefore by Pythagoras theorem

6²+x²=12²

36+x²=144

x²=144-36

x²=108

x=√108

x=√2×2×3×3×3

x=2×3√3

x=6√3 m or 10.39 approx

Answer 2

Answer:

6√3 m

Step-by-step explanation:

check the image for solution!!

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