Question

cheak whether the following are quadratic equation (X - 2) (X + 1) = (X - 1) (X + 3) ​

Answer 1

Answer:

(x - 2) (x + 1) = (x - 1) (x + 2)

x( x + 1) -2(x + 1) = x (x + 2) -1(x + 2)

x² + x -2x -2 = x² + 2x -x - 2

-x - 2 = x - 2

-2x = 0

x = 0

No, it is not Quadratic equation

While comparing with general form ax² + bx + c = 0

Answer 2

☑️ Given Equation :

(x - 2) (x + 1) = (x - 1) (x + 3)

━━━━━━━━━━━━━━━━━━━━━━━━

☑️ To Check :

Whether the given equation is quadratic.

━━━━━━━━━━━━━━━━━━━━━━━━

$\huge{\{\red{\boxed{\boxed{\sf{\underline{\underline{\orange{\bigstar{.SoLutiOn.}}}}}}}}}$

━━━━━━━━━━━━━━━━━━━━━━━━

$\implies$ (x - 2) (x + 1) = (x - 1) (x + 3)

$\implies \: x(x + 1) - 2(x + 1) = x(x + 3) - 1(x + 3)$

$\implies \: {x}^{2} + x - 2x - 2 = {x}^{2} + 3x - x - 3$

$\implies \: {x}^{2} - x - 2 = {x}^{2} + 2x - 3$

On taking all the terms one side,

$\implies \: {x}^{2} - x - 2 - {x}^{2} - 2x + 3 = 0$

$\implies \: - x - 2 - 2x + 3 = 0$

$\implies \: - 3x + 1 = 0$

$\implies \: 3x - 1 = 0$

Here, we found an equation of degree 1 as the equation is not of the form a$\underline{x}^2$+ bx + c = 0.

$\therefore$ The given equation is not quadratic.

━━━━━━━━━━━━━━━━━━━━━━━━

⋰ Hope It Will Be Helpful To You Mate ⋱

#be_brainly