Question

Check, 0 is a term of the AP : 31, 28, 25, …. ?

Answer 1

Answer:

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Answer 2

Answer:

No

Step-by-step explanation:

Given:

a = 31 , d = -3 , A of n = 0

we know that,

A of n = a + (n-1)d

on subs the values we get,

0 = 31 + ( n-1)-3

$\frac{-31}{3}$ = n-1

n = 9.33

as the value of n is in decimal we can conclude that 0 is not a term in the given AP