Question

check a-8/3=7-4a/7 in which a=77/19​

Answer 1

$\sf{Given:- } \\ {a= \frac{77}{19} }$

$\large \sf \bf{a - \frac{8}{3} = 7 - \frac{4a}{7} }$

Put the value of a;

$\frac{77}{19} - \frac{8}{3} = 7 - \frac{4 \times \frac{77}{19} }{7}$

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$\sf{first \: let's \: solve \: this:-} \\ \boxed{ \frac{4 \times \frac{77}{19} }{7} }$

$\sf = > 4 \times \frac{11}{19} = \frac{44}{19}$

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$\sf = > \frac{77}{19} - \frac{8}{3} = \frac{7}{1} - \frac{44}{19}$

Solve it by taking it L.H.S. and R.H.S.

L.H.S.

$\sf = > \frac{77}{19} - \frac{8}{3}$

L.C.M. of 19 and 3=3×19=57

$= > \frac{77}{19} \times \frac{3}{3} = \frac{231}{57}$

$= > \frac{8}{3} \times \frac{19}{19} = \frac{152}{57}$

$= > \frac{231 - 152}{57} = \frac{79}{57}$

R.H.S.

$= > \frac{7}{1} - \frac{44}{19}$

Take L.C.M. of 1 and 19=19

$= > \frac{7}{1} \times \frac{19}{19} = \frac{133}{19}$

$= > \frac{44}{19} \times \frac{1}{1} = \frac{44}{19}$

$= > \frac{133 - 44}{19} = \frac{89}{19}$

$\frac{79}{57} \not = \frac{89}{19}$

L.H.S. is not equals to R.H.S.

$\sf{so, \: a - \frac{8}{3} \not = 7 - \frac{4a}{7} }$

${\large { \color{aqua} {\boxed{ \color{pink}{\sf {❥Hope \: it \: helps \: you....}}}}}}$