Math, asked by kanakamsiddhu423, 9 months ago






Check and discuss the above relations in the case of angles between 0º and 90º,

whether they hold for these angles or not?

So, sin (90o − A) = cos A cos (90o − A) = sin A

tan (90o − A) = cot A and cot (90o − A) = tan A

sec (90o − A) = cosec A cosec (90o − A) = sec A
solutions. ​

Answers

Answered by Ankita2602
0

Step-by-step explanation:

Check and discuss the above relations in the case of angles between 0º and 90º,

whether they hold for these angles or not?

So, sin (90o − A) = cos A cos (90o − A) = sin A

tan (90o − A) = cot A and cot (90o − A) = tan A

sec (90o − A) = cosec A cosec (90o − A) = sec A

solutions.

Answered by rajaniprasad315
0

Answer:

Step-by-step explanation:

Check and discuss the above relations in the case of angles between 0º and 90º,

whether they hold for these angles or not?

So, sin (90o − A) = cos A cos (90o − A) = sin A

tan (90o − A) = cot A and cot (90o − A) = tan A

sec (90o − A) = cosec A cosec (90o − A) = sec A

solutions.

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