Check graphically whether the pair of equations
x + 3y = 6 1)
2x - 3y = 12 2)
is consistent. If so, solve them graphically.
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Answered by
3
x+3y = 6
1x + 3y - 6=0
comparing with a1x+b1y+c1=0
therefore a1=1,b1=negative 6
2x-3y-12=0
comparing with a2xb2y+c2=0
therefore a2=2,b2=negative 3,c2=negative 12
by the way all the letters apart from the question are supposed to be small anc at the bottom
1x + 3y - 6=0
comparing with a1x+b1y+c1=0
therefore a1=1,b1=negative 6
2x-3y-12=0
comparing with a2xb2y+c2=0
therefore a2=2,b2=negative 3,c2=negative 12
by the way all the letters apart from the question are supposed to be small anc at the bottom
keziah3333:
your welcome
Answered by
0
x+3y = 6
1x + 3y - 6=0
comparing with a1x+b1y+c1=0
therefore a1=1,b1=negative 6
2x-3y-12=0
comparing with a2xb2y+c2=0
therefore a2=2,b2=negative 3,c2=negative 12
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