check it out guys here is again a simple question... try to do it in copy plzzzzzzzzzzz....
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Answered by
2
Heya...
Here is your answer --
Given, x = -5
So, we will take 5 times -5 = -25
In the LHS, we have 5x
Now, for the RHS, we can use 4x-5
So the equation formed will be :--
5x = 4x-5
SOLUTION
5x = 4x-5
5x-4x = -5
x = -5 (Given)
HOPE IT HELPS...!!
Here is your answer --
Given, x = -5
So, we will take 5 times -5 = -25
In the LHS, we have 5x
Now, for the RHS, we can use 4x-5
So the equation formed will be :--
5x = 4x-5
SOLUTION
5x = 4x-5
5x-4x = -5
x = -5 (Given)
HOPE IT HELPS...!!
Answered by
1
heya!
Solution needed => x = ( -5 )
Thus, we'll have to take 5 times ( -5 ), that is -25.
For the LHS, 5x can be taken. Now we're left with the RHS, without which an equation can't be formed. 4x - 5 can be taken as the RHS.
So, as we're done with both the sides, now can check if we're forming the linear equation.
Equation formed =>
5x = 4x - 5
5x - 4x = -5
x = -5 ( solution needed )
#hope it helps!
Solution needed => x = ( -5 )
Thus, we'll have to take 5 times ( -5 ), that is -25.
For the LHS, 5x can be taken. Now we're left with the RHS, without which an equation can't be formed. 4x - 5 can be taken as the RHS.
So, as we're done with both the sides, now can check if we're forming the linear equation.
Equation formed =>
5x = 4x - 5
5x - 4x = -5
x = -5 ( solution needed )
#hope it helps!
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