Math, asked by premlata2278, 9 months ago

Check out whether the graph according to the question is correct. (If wrong then kindly solve the problem)
Que. solve graphically
the system of
linear equations
4x-5y +16=0 and 2x+y-16=0
Determine the vertices of the triangle formed by these lines and the x-axis.

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Answers

Answered by Anonymous
128

QUESTIONS

Draw the graph of the equations 4x – 5y + 16 = 0 and 2x + y – 6 = 0. Determine the vertices of the triangle formed by these lines and the x-axis.

SOLUTION:-

Graph of 4x-5y+16=0

=>5y=4x+16

=>y=(4x+16)/5......(1)

Putting x=-4 in (1) we get :y=0

Putting x=1 in (1) we get :y=4

Putting x =6 in (1) we get :y=8

Thus we have the following table for 4x-5y+16=0

_________

x | 4 | 1 | 6 |

y | 0 | 4 | 8 |

Graph of 2x+y-6=0

=>y=(6-2x)........(2)

Putting x =0 in (2) we get : y=6

Putting x=2 in (2) we get :y=2

Putting x=3 in (2) we get :y=0

Thus we have the following table for 2x+y-6=0

_________

x | 0 | 2 | 3 |

y | 6 | 2 | 0 |

In the above figure by plotting these points we get the solution of this equation on which the two lines intersect i.e B(1,4)

Therefore x=1 ,y=4 is the solution of the given system of equation

These lines form triangle BAR with x-axis ,whose vertices are B(1,4),A(-4,0) and R(3,0)

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