Math, asked by premlata2278, 10 months ago

Check out whether the graph according to the question is correct. (If wrong then kindly solve the problem)
Que. solve graphically
the system of
linear equations
4x-5y +16=0 and 2x+y-16=0
Determine the vertices of the triangle formed by these lines and the x-axis.

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Answers

Answered by Anonymous
128

QUESTIONS

Draw the graph of the equations 4x – 5y + 16 = 0 and 2x + y – 6 = 0. Determine the vertices of the triangle formed by these lines and the x-axis.

SOLUTION:-

Graph of 4x-5y+16=0

=>5y=4x+16

=>y=(4x+16)/5......(1)

Putting x=-4 in (1) we get :y=0

Putting x=1 in (1) we get :y=4

Putting x =6 in (1) we get :y=8

Thus we have the following table for 4x-5y+16=0

_________

x | 4 | 1 | 6 |

y | 0 | 4 | 8 |

Graph of 2x+y-6=0

=>y=(6-2x)........(2)

Putting x =0 in (2) we get : y=6

Putting x=2 in (2) we get :y=2

Putting x=3 in (2) we get :y=0

Thus we have the following table for 2x+y-6=0

_________

x | 0 | 2 | 3 |

y | 6 | 2 | 0 |

In the above figure by plotting these points we get the solution of this equation on which the two lines intersect i.e B(1,4)

Therefore x=1 ,y=4 is the solution of the given system of equation

These lines form triangle BAR with x-axis ,whose vertices are B(1,4),A(-4,0) and R(3,0)

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