Question

check the atachment above and please answer me this it is rational number qution and if u answer me correct i will mark u brainliest​

Answer 1

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Answer 2

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2. $x = \frac{224}{525}$

3. $\frac{97}{33}$

4. $x = \frac{17}{ - 9}$

5. $\frac{ - 185}{24}$

6. $\frac{96}{ - 91}$

7. $- \frac{9}{7}$

8. $\frac {7}{5}$

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2.

Let the other number be x

Now,

$x \times \frac{ - 15}{14} = \frac{ - 16}{35}$

$x = \frac{ - 16}{35} \div \frac{ - 15}{14} = \frac{ - 16}{35} \times \frac{14}{ - 15}$

$x = \frac{224}{525}$

$\therefore \: the \: other \: number \: is \: \frac{224}{525} .$

3.

According to the question, we want to divide the addition of two rational numbers and difference of the two rational numbers.

First we find the sum,

$\frac{65}{12} + \frac{8}{3} = \frac{65 + 32}{12} = \frac{97}{12}$

Now we find their difference,

$\frac{65}{12} - \frac{8}{3} = \frac{65 - 32}{12} = \frac{33}{12}$

Now we divide the both

$\frac{97}{12} \div \frac{33}{12} = \frac{97}{12} \times \frac{12}{33} = \frac{97}{33}$

$\therefore \: the \: answer \: is \: \frac{97}{33} .$

4.

$\frac{5}{9} \div x = \frac{ - 5}{17}$

$x = \frac{ 17}{ - 5} \times \frac{5}{9} = \frac{ 17}{ - 9}$

$\therefore \: the \: value \: of \: x \: is \: \frac{17}{ - 9}$

5.

$( \frac{ - 3}{2} \div \frac{9}{8} ) + ( \frac{9}{5} \times \frac{ - 10}{3}) - ( \frac{1}{2} \div \frac{4}{3} )$

$= ( \frac{ - 3}{2} \times \frac{8}{9} ) + ( - 6) - ( \frac{1}{2} \times \frac{3}{4} )$

$= ( \frac{ - 4}{3} ) + ( - 6) - ( \frac{3}{8} ) = \frac{ - 4}{3} - 6 - \frac{3}{8}$

$= \frac{ - 32 - 144 - 9}{24} = \frac{ - 185}{24} .$

6.

$Reciprocal \: of \: \frac{ - 7}{16} \: is \: \frac{16}{ - 7}$

$\frac{6}{13} \times \frac{16}{ - 7} = \frac{96}{ - 91}$

7.

$Additive \: inverse \: of \: \frac{9}{7} \: is \: - \frac{9}{7} .$

8.

$Multiplicative \: inverse \: of \: \frac{5}{7} \: is \: \frac{7}{5} .$