Physics, asked by ibrahimibbu0747, 6 months ago

Check the correctness of the equation v^(2)=u^(2)+2ax where u v are initial and final velocity is acceleration and x is distance.​

Answers

Answered by anurag2147
2

Answer:

v² =u² +2ax

dimension of v = dimension of u

L²/T² = L²/T²

dimension of v= dimension of 2as

L²/T² = L/T² × L

L²T² = L²/T²

here , dimension of v = dimension of u and dimension of v= dimension of 2as

so these equation is dimensionally correct

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