Question

Check the. correctness of the relation
sn=u+a/2(2n-1)

Answer 1

$\large\rm { s_{nth} = μ + \frac {a}{2} (2n \ - \ 1)}$

The real formula is;

$\large\rm { μ(1) + \frac {1}{2} (1) \ (2n \ - \ 1)}$

Where 1 represents 1 sec as times

LHS = [ L ]

[ L ] = $\large\rm { μ(1) = [LT^{-2}][T]}$

= [ L ]

$\large\rm { \frac {a}{a} (1)[2n \ - \ 1] = LT^{-2} }$ [ T ] [ T ]

= [ L ]

Now,

[ L ] = [ L ] + [ L ]

hence the formula is correct

Answer 2

Answer:

\large\rm { s_{nth} = μ + \frac {a}{2} (2n \ - \ 1)}s

nth

=μ+

2

a

(2n − 1)

The real formula is;

\large\rm { μ(1) + \frac {1}{2} (1) \ (2n \ - \ 1)}μ(1)+

2

1

(1) (2n − 1)

Where 1 represents 1 sec as times

LHS = [ L ]

[ L ] = \large\rm { μ(1) = [LT^{-2}][T]}μ(1)=[LT

−2

][T]

= [ L ]

\large\rm { \frac {a}{a} (1)[2n \ - \ 1] = LT^{-2} }

a

a

(1)[2n − 1]=LT

−2

[ T ] [ T ]

= [ L ]

Now,

[ L ] = [ L ] + [ L ]

hence the formula is correct