Check the dimensional correctness of the relation g=GM/r²
Answers
Answered by
1
Explanation:
We know ForceF=mass×acceleration----------(1)
And given ForceF=rmv2----------(2)
Equating 1 and 2 dimensionaly we get ,
ma=rmv2
MLT−2=ML2T−2L−1
MLT−2=MLT−2
Answered by
1
Explanation:
Correct option is
A
M
−1
L
3
T
−2
- Gravitational force acting between two objects of masses m.
1
and m
2
- separated by distance r, F=
r
2
Gm
1
m
2
⟹ G=
m
1
m
2
Fr
2
- Thus dimensional formula of G is
[M]
2
[MLT
−2
][L]
2
- ⟹ G=M
−1
L
3
T
−2
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