Question

check the eq. v=u + at​

Answer 1

Answer:

dimentionally correct

Explanation:

because here:

     v=velocity=[Lt^-1]              

and u also=[Lt^-1]

but a x t= [Lt^-2] x [t^1]=[Lt^-1]

so in dimention form equatio we have:

[v]=[u]+[a][t]

[Lt^-1]=[Lt^-1]+[Lt^-1]

hence

[Lt^-1]=[Lt^-1]