Math, asked by Megavannan1, 1 year ago

Check the following are the zeros of the polynomial:

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Answers

Answered by VIDHII
1
h(y)= -2y^2-3y+8-3y^3
If (y=1) = -2-3+8-3
=-5+5
=0
Answered by ravalikachinni
1

Answer:

➡️ p(y) = -2y²-3y+8-3y³

➡️ p(y) = 1

p(1) = -2(1)²-3(1)+8-3(1)³

= -2 - 3 + 8 - 3

= - 5 + 5

= 0

zero of the above polynomial is 1 .

hope this helps uh...!!

@Rajula Ravalika

: )

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