Check the following are the zeros of the polynomial:
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1
h(y)= -2y^2-3y+8-3y^3
If (y=1) = -2-3+8-3
=-5+5
=0
If (y=1) = -2-3+8-3
=-5+5
=0
Answered by
1
Answer:
➡️ p(y) = -2y²-3y+8-3y³
➡️ p(y) = 1
p(1) = -2(1)²-3(1)+8-3(1)³
= -2 - 3 + 8 - 3
= - 5 + 5
= 0
zero of the above polynomial is 1 .
hope this helps uh...!!
@Rajula Ravalika
: )
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