CBSE BOARD XII, asked by shraddhabhure6387, 1 month ago

Check the injectivity and surjectivity of the following functions:
(i)f : N → N given by f(x) = x2

Answers

Answered by anu82devi
0

Answer:

injective but not surjective

Explanation:

f(x)=x ^2

 

It is seen that for x,y∈N,

f(x)=f(y)⇒x ^2 = Y^2  

⇒x=y

∴f is injective

Now, 2∈N, But, there does not exist any x

in N such that f(x)=x^2 = 2  

 

∴f is not surjective.

Hence, function f is injective but not surjective.

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