Question

Check the integral


is convergent or divergent.​

Answer 1

Answer:

divergent

Step-by-step explanation:

as if likits are+ and - infinity in such case integral are divergent

Answer 2

Answer:

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Step-by-step explanation:

We will call these integrals convergent if the associated limit exists and is a finite number (i.e. it's not plus or minus infinity) and divergent if the associated limit either doesn't exist or is (plus or minus) infinity.

An improper integral is said to converge if its corresponding limit exists; otherwise, it diverges. The improper integral in part 3 converges if and only if both of its limits exist. Evaluate the following improper integrals. [t]∫∞11x2 dx = limb→∞∫b11x2 dx = limb→∞−1x|b1=limb→∞−1b+1=1.

Ratio test

If r < 1, then the series is absolutely convergent. If r > 1, then the series diverges. If r = 1, the ratio test is inconclusive, and the series may converge or diverge.