Question

check wheather -2 and 2 are the zeroes of x2-4
That is not x2 it was x square​

Answer 1

Answer:

${x}^{2} - \: 4 \\ it \: can \: be \: written \: as \\ (x + 2)(x - 2) \\ zeroes : \frac{ + }{} 2 \\ let \: check : \\ if \: x = 2 \: then \\ {x}^{2} - 4 = {2}^{2} - 4 = 4 - 4 = 0 \\ if \: x = - 2 \: \: then \\ {x}^{2} - 4 = { (- 2)}^{2} - 4 = 4 - 4 = 0$