Check wheather 6^n can end with the digit 0 or any natural number n.
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Answered by
4
6^n=(2×3)^n
6^n=2×3×2×3×2×3...
so there CAN never be presence of 5 in prime factorisation of 6^n BUT this is necessary for a number TO have 2 and 5 in prime factorisation to end with a zero ..
HENCE NO.
6^n=2×3×2×3×2×3...
so there CAN never be presence of 5 in prime factorisation of 6^n BUT this is necessary for a number TO have 2 and 5 in prime factorisation to end with a zero ..
HENCE NO.
Answered by
2
N is a natural no.
6^n is divisible by 5
But the prime factor of 6 are 2 and 3
6^n=(2*3)
in the prime factor of 6^n there is no factor of 5
Therefore 6^n do not end with 0
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