Question

Check wheather the equation is dimensionally correct .v^2=u^2+2as^2

Answer 1

We can check the correctness of equation by Dimensional Analysis.

Equation: V²-U²=2as

where V=u=velocities = Dimension=LT⁻¹

a= acceleration=ΔV/T=LT⁻¹/T=LT⁻²

S=Distance=L

R.H.S=2as=2x[LT⁻²]x[L]=[L²T⁻²]

L.H.S=v²-u²=[LT⁻¹]²=[L²T⁻²]

Therefore  L.H.S=R.H.S

Hence we can say equation is correct

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