Check whether 1 is a zero of the polynomial p(x) =x^6-x^5-x^4-x^3-x^2-x+1=0
Answers
Answer:
Step-by-step explanation:
Answer: Zeros of (I) are a=0, 3u/4; zero of (II) is r= 4/3π
Solution:
The Zeros of the polynomials
3au - 4a² ………………………………….(I) and
3πr - 4 ……………………………………..(II)
can be found by solving the two equations
3au - 4a² = 0 …………………………………………………………………….…………(1)
and 3πr - 4 = 0 ……………………………………………………………………….…..(2)
Since (I) is a polynomial of degree two in a, it will have two roots; and (II) being a first degree polynomial in r will have only one root. (1) being a quadratic in a can be solved by factorisation or by using the formula or by method of completion of square.
Factorizing (1),
a(3u - 4a) = 0
Or, a = 0 , 3u - 4a = 0
Or, a = 0, 3u = 4a
Or, a=0, a = 3u/4
∴ The zeros of the polynomial 3au - 4a² are
a = 0 and a = 3u/4
The zero of (2) is obtained by solving for r.
3πr - 4 = 0
Or, 3πr = 4 (Taking -4 to right-side and changing the sign)
Or, r = 4/3π
∴The zero of the polynomial 3πr - 4 is
r = 4/3π
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