check whether 101 is a term of the list of numbers 2,4,6,8,10
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Answer:
An=a+(n-1)d
Step-by-step explanation:
A=2 (first term)
d=t2-t1(term2-term1)
=4-2
=2.
let us assume 101 is a term of given Ap,
so,an=101
an=a+(n-1)d (formulae)
101 =2+(n-1)2 (substituting the values)
101-2=(n-1)2
100=(n-1)2
100/2=n-1
50=n-1
50+1=n
hence,n=51.
therefore,we can conclude that 101 is the 51th term of Ap i.e 101 is one of the term in given Ap.
Goodluck.
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