concave lens has a focal length 10 cm and object 2.5 cm height is placed at 30 cm from the lens determine the size and the position of the image
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- Size and the position of the image is 0.625 and -7.5 cm respectively.
Given-
Focal length of the concave lens is negative so f = -10 cm
Object distance from the lens is u = -30 cm
As, we know that
1/f = 1/v - 1/u where f is the focal length, v is the image distance from the lens and u is the object distance from the lens.
By putting the values in the above formula we get -
v = - 7.5 cm
And we know that magnification is equals to height of the image to the height of the object.
So, m = v/u = H1/H0
By putting the values we get -
H1/2.5 = -7.5/ -30
H1= 0.625
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10
Answer:
the answer is 0.625 and 7.5
hope this helped you
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