Check whether 2016 × 2017 × 2018 is divisible by 3 ? Justify
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if any one of 2016 , 2017 , 2018 is divisible by 3 then the whole product is divisible by 3
2016
2+0+1+6=9
since 9 is divisible by 3 hence 2016 is divisible by 3 hence the whole product is divisible by 3
DIVISIBLITY TEST OF 3 : SUM OF THE DIGITS OF THE NUMBER MUST BE DIVISIBLE BY 3
2016
2+0+1+6=9
since 9 is divisible by 3 hence 2016 is divisible by 3 hence the whole product is divisible by 3
DIVISIBLITY TEST OF 3 : SUM OF THE DIGITS OF THE NUMBER MUST BE DIVISIBLE BY 3
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