check whether 21 by 112 will have terminating decimal expansion or not
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112 = 2 × 2 × 2 × 2 × 7
→ 112 = 2⁴ × 7
=> 21/112 = 21/(2⁴ × 7)
= 3/2⁴
= 3/(2⁴ × 5°) (5° = 1)
The denominator is in the form of 2ⁿ × 5^m. So,it is terminating decimal.
→ 112 = 2⁴ × 7
=> 21/112 = 21/(2⁴ × 7)
= 3/2⁴
= 3/(2⁴ × 5°) (5° = 1)
The denominator is in the form of 2ⁿ × 5^m. So,it is terminating decimal.
Answered by
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112=2^4×7
and 21/112=3/2^4×5^0
i.e. denominator is of the form 2^n ×5^m
i.e it has teminating decimal expension.
and 21/112=3/2^4×5^0
i.e. denominator is of the form 2^n ×5^m
i.e it has teminating decimal expension.
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