Check whether 22k is a term of an A.P:-(-4),1,6,11
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first term: (-4)
common difference: [1-(-4)] = 5
we have to check whether 22k is one of the terms of this AP or not then...
n th term = a+ (n-1)d
22k = (-4) + (n-1)(5)
(22k + 4 )÷5 = n-1
(22k +9) ÷ 5= n
...there will be two cases I will give further solution in the photo...
value of n must be a whole number .....
common difference: [1-(-4)] = 5
we have to check whether 22k is one of the terms of this AP or not then...
n th term = a+ (n-1)d
22k = (-4) + (n-1)(5)
(22k + 4 )÷5 = n-1
(22k +9) ÷ 5= n
...there will be two cases I will give further solution in the photo...
value of n must be a whole number .....
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