solve 3x2-5x+2=0 by using square form method in quadratic equation
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Answer:
Step-by-step explanation:
3x^2-5x+2=0
a=3,b=-5,c=2
D=b^2-4ac
=(-5)^2-4(3)(2)
=25-24
=1
D=+1 or -1
x=5+or-1/6
=5+1/6 or 5-1/6
=6/6 or4/6
=1 or2/3
Therefore,
THE ZEREOS ARE 1 OR 2/3
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