Check whether (3, 2), (- 2 - 3) and (2, 3) are the vertices of a right angled triangle
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Answer:
in a right angle triangle
hyp^2=opp^2+adj^2.
distance between two points is
√(x1-x2)^2+(y1-y2)^2
AB=√(3-(-2))^2+(2-(-3))^2
=√5^2+5^2
=√25+25
=√50
BC=√(-2-2)^2+(-3-3)^2
=√(-4)^2+(-6)^2
=√16+36
=√52
CA=√(3-2)^2+(3-2)^2
=√1^2+1^2
=√1+1
=√2
BC^2=AB^2+CA^2
√52^2=√50^2+√2^2
52=50+2
52=52
hence proved...
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