Math, asked by sk8037514, 11 months ago


Check whether (3, 2), (- 2 - 3) and (2, 3) are the vertices of a right angled triangle

Answers

Answered by ashu509465
6

Answer:

in a right angle triangle

hyp^2=opp^2+adj^2.

distance between two points is

√(x1-x2)^2+(y1-y2)^2

AB=√(3-(-2))^2+(2-(-3))^2

=√5^2+5^2

=√25+25

=√50

BC=√(-2-2)^2+(-3-3)^2

=√(-4)^2+(-6)^2

=√16+36

=√52

CA=√(3-2)^2+(3-2)^2

=√1^2+1^2

=√1+1

=√2

BC^2=AB^2+CA^2

√52^2=√50^2+√2^2

52=50+2

52=52

hence proved...

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plz.

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