Question

Check whether 3 and -2 are the zeros of the polynomial p(x)=x2-×-6

Answer 1

p(x) = x2 × (-6)

=> put 3 in place of x

3 = (3×2) × (-6)

3= 6× -6

3= - 36

= -36/3

= -12.

p(x) = x2 × (-6)

=> put -2 in place of x

-2= (-2 × 2) × (-6)

-2= -4 × -6

-2 = 24

= 24/-2

= -12