Question

check whether 3 and -2 are the zeros of the polynomial p(x)=x2-x- 6
Do it in step by step....
1st answer brainliest...
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Answer 1

First put the value of x as 3
(3)^2 - 3 - 6 = 0
9 - 3 - 6 = 0
6-6=0
It us the zeroes of the polynomial
Now put the value of x as - 2
(-2)^2 - (-2) - 6 = 0
4 + 2 - 6 = 0
6-6=0
It is also the zeroes of the polynomial
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Answer 2

$p(x) = {x}^{2} - x - 6 \\ \\ p(x) = {x}^{2} - 3x + 2x - 6 \\ \\ p(x) = x(x - 3) + 2(x - 3) \\ \\ p(x) = ( x + 2)(x - 3) \\ \\ now \\ \\ p( - 2) = ( - 2 + 2)( - 2 - 3) = 0 \\ \\ also \\ \\ p(3) = (3 + 2)(3 - 3) = 0 \\ \\ therefore \: 3 \: and \: - 2 \: are \: zeroes \: of \: p(x)$

hope it helps.