check whether 3n-3 are the zeroes of the polynomial xsqure - 9 or not
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p(x)=x²-9
p(3)=3²-9
=9-9=0
p(-3)=(-3)²-9
=9-9=0
p(3)=0 and p(-3)=0
∴3 and -3 are zeroes of p(x)=x²-9
p(3)=3²-9
=9-9=0
p(-3)=(-3)²-9
=9-9=0
p(3)=0 and p(-3)=0
∴3 and -3 are zeroes of p(x)=x²-9
ammunazriya:
I think the answer is correct
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3n-3 is not the zero of polynomial
here,
3n-3=0
3n=3
n=1
after putting value of X
p (x )=x^2-9
p (1)=1^2-9
= -8
here,
3n-3=0
3n=3
n=1
after putting value of X
p (x )=x^2-9
p (1)=1^2-9
= -8
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