Question

Check whether 6,8,10 from phythagores thems are not? Solve and how?

Answer 1

Heya ..!

Let AB =6cm
BC=8cm
AndCA=10cm

So acc. To theorem sq. Of one side should be the sum of sq. Of other two sides

So here (AB)2 + (BC)2 = (CA)2
(6)2+(8)2=(10)2
36+64=100



Hence proved...!
Hope this helps u...!
#bipasha

Answer 2

let a=6, b=8 , c=10
so now
A2 + b2= C2 (we have to prove)
36 + 64=100
which is the square of c


hence it forms Pythagoras triplet